Interesting about the picture . . .
of the 16 numbers listed, 12 of them are the same two numbers.
Does this seem more likely or less likely to you than 7 straight.
For the answer, I asked Ed Meyer, a Physics PHD/handicapper/friend of Pregame.com - with student Joe Luchsinger they determined the following . . .
The probability of any two PARTICULAR numbers (e.g., 1 and 2) occurring in exactly 12-of-16 spins is (1/19)^12 * (18/19)^4 * 16!/(12!4!).
To get the probability of ANY two numbers, we have to multiply this by the number of ways two numbers can be chosen from 38.
This is: 38*37/2
So, I get 1 of of 2,147,538,121 or about one out of two billion that the next 16 spins of a roulette wheel will land on any 2 of the 38 numbers in 12 of the 16 spins.